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aflati perechile de numere naturale a si b,stiind ca:a) (a,b)=10;a+b=150 b) (a,b)=6;a ori b=1620

Răspuns :

(a,b)=10
=> a=10k (k, l)=1
b=10l
10k+10l=150
10 (k+l)=150
k+l=15
1) k=1 => a=10
=> l=14 => b=140

2) k=2 => a=20
=> l=13 => b=130

3) k=3 => a=30
=> l=12 => b=120

4) k=4 => a=40
=> l=11 =>b=110

5) k=5 =>a=50
=> l=10 =>b=100

6) k=6=> a=60
=> l=9=>b=90

7) k=7=> a=70
=> l=8=> b=80

8) k=8=> a=80
=>l=7 => b=70

9) k=9 => a=90
=> l=6 => b=60

10) k=10 => a=100
=> l=5 => b=50

11) k=11 => a=110
=> l=4 => b=40

12) k=12 => a=120
=> l=3 => b=30

13) k=13 => a=130
=> l=2 => b=20

14) k=14 => a=140
=> l=1 => b= 10

b) (a, b)=6 ; a•b=1620
=> a=6k
b=6l
6k•6l=1620
36kl=1620
kl= 45

1) k=1 => a=6
=> l= 45 => b=270

2) k=3 => a=18
=> l=15 => b=60

3) k=5 => a=30
=> l=9 => b=54

4) k=9 => a=54
=> l=5 => b=30

5) k=15 => a=90
=> l=3 => b=18

6) k=45 => a=270
=> l=1 => b=6