a moli CH3-CH3
b moli CH2=CH-CH3+Br2----> CH2Br-CHBr- CH3
MASA solutiei de brom creste cu masa de propena care aditioneaza bromul din solutie:
calculez moli propena: b= 84mg/ 42mg/mmol= 2 mmol propena
calculez nr.moli total din amestec: n= 100cm³/22,4cm³/22,4cm³/mmol=
n= 4,464mmol= a+b---> a= 2,464mmol etan
in 4,464mmol.amestec........2 mmol propena
100...........................................c%================>
M,propan =(3x12gC+6gH)g/mol= 42g/mol= 42mg/mmol
