1. piatra vanata = CuSO4·5H2O MCuSO4·5H2O = 250g/mol
MCuSO4 = 160g/mol
250g piatra vanata ......contine.........160gCuSO4
25g........................................................md = 16g ⇒ c = 16·100/200 = 8%
2. x·100/(125+x) = 5 20x = 125+x 19x = 125 x = 6,579g
3. initial : msi = 400g ci = 10% mdi = 40g
se evapora : m g H2O
final : ms = 400-m md = mdi = 40 g c = 40%
40·100/(400-m) = 40 100 = 400 - m m = 300g
5. n = 9,8/98 = 0,1 moli cM = 0,1/4 = 0,025 moli/l