[tex]\frac{3x-5}{2}-\frac{5x+1}{4}=\frac{2x+6}{8}-\frac{3x-12}{6}-1 \\
\frac{2(3x-5)-5x-1}{4}= \frac{3(2x+6)-4(3x-12)-24}{24}\\
\frac{6x-10-5x-1}{4}= \frac{6x+18-12x+48-24}{24}\\
\frac{x-11}{4}= \frac{42-6x}{24}\\
24(x-11)=4(42-6x)\\
24x-264=168-24x\\
24x+24x=168+264\\ 48x=432\\ x=432:48\\x=9\\
[/tex]
S={9}