[tex]cosf= \frac{ \sqrt{3} }{ \sqrt{2} } = \frac{ \sqrt{6} }{2} \\ sinf = \frac{1}{ \sqrt{2} } = \frac{ \sqrt{2}}{2} [/tex]
Nu exista un fi care sa satisfaca ambele valori, demonstratie:
[tex]sin^{2} f + cos^{2} f = 1 \Rightarrow(\frac{ \sqrt{2} }{2})^{2} + (\frac{ \sqrt{6} }{2})^{2} =1 \Rightarrow \frac{2}{4}+ \frac{6}{2} = 1 \Rightarrow \\ \Rightarrow \frac{2+12}{4} =1 \Rightarrow \frac{14}{4} = 1 (F) [/tex]
=> fi ∈ {Ф}
