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prin metoda mersului invers e-127-805+574+135+6-308=726

Răspuns :

e-127-805+574+135+6=1034
e-127-805+574+135=1028
e-127-805+574=893
e-127-805=319
e-127=1124
e=1251
e=726+308-6-135-574+805+127
e=1034-6-135-574+805+127
e=1028-135-574+805+
127
e=893-574+805+127
e=319+805+127
e=1124+127
e=1251