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aratati ca numarul a= 3 la puterea 2n+2 * 4 la puterea 2n +3 - 2 la puterea 2n+1 * 6 la puterea 2n+3 este patrat perfect va rog mult

Răspuns :

[tex]\it 3^{2n+2}\cdot4^{2n+3}-2^{2n+1}\cdot6^{2n+3} =3\cdot3^{2n+1}\cdot4^2\cdot4^{2n+1} - \\\;\\ -\it2^{\it2n+1}\cdot \it6^2\cdot \it6^{\it2n+1} = 48\cdot12^{2n+1}-36\cdot12^{2n+1} =12^{2n+1}(48-36) = \\\;\\ =12^{\it2n+1}\cdot \it12=\it12^{2n+2} = (12^{n+1})^2 [/tex]